1.5t^2-26.8-16100=0

Solution for 1.5t^2-26.8-16100=0 equation:

1.5t^2-26.8-16100=0

We add all the numbers together, and all the variables

1.5t^2-16126.8=0

a = 1.5; b = 0; c = -16126.8;
Δ = b2-4ac
Δ = 02-4·1.5·(-16126.8)
Δ = 96760.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{96760.8}}{2*1.5}=\frac{0-\sqrt{96760.8}}{3}
=-\frac{\sqrt{}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{96760.8}}{2*1.5}=\frac{0+\sqrt{96760.8}}{3}
=\frac{\sqrt{}}{3}
$